通过下面几个问题来更好理解golang 的数组和切片
类型
数组是值类型,将一个数组赋值给另一个数组时,传递的是一份拷贝。
切片是引用类型,切片包装的数组称为该切片的底层数组。
我们来看一段代码12345678910111213//a是一个数组,注意数组是一个固定长度的,初始化时候必须要指定长度,不指定长度的话就是切片了a := [3]int{1, 2, 3}//b是数组,是a的一份拷贝b := a//c是切片,是引用类型,底层数组是ac := a[:]for i := 0; i < len(a); i++ {a[i] = a[i] + 1}//改变a的值后,b是a的拷贝,b不变,c是引用,c的值改变fmt.Println(a) //[2,3,4]fmt.Println(b) //[1 2 3]fmt.Println(c) //[2,3,4]make
make 只能用于slice, map 和 channel, 所以下面一段代码生成了一个slice,是引用类型123456789101112s1 := make([]int, 0, 3)for i := 0; i < cap(s1); i++ {s1 = append(s1, i)}s2 := s1for i := 0; i < len(a); i++ {s1[i] = s1[i] + 1}fmt.Println(s1) //[1 2 3]fmt.Println(s2) //[1 2 3]当对slice append 超出底层数组的界限时
12345678910111213141516171819202122232425262728293031323334353637383940//n1是n2的底层数组n1 := [3]int{1, 2, 3}n2 := n1[0:3]fmt.Println("address of items in n1: ")for i := 0; i < len(n1); i++ {fmt.Printf("%p\n", &n1[i])}//address of items in n1://0xc20801e160//0xc20801e168//0xc20801e170fmt.Println("address of items in n2: ")for i := 0; i < len(n2); i++ {fmt.Printf("%p\n", &n2[i])}//address of items in n2://0xc20801e160//0xc20801e168//0xc20801e170//对n2执行append操作后,n2超出了底层数组n1的jn2 = append(n2, 1)fmt.Println("address of items in n1: ")for i := 0; i < len(n1); i++ {fmt.Printf("%p\n", &n1[i])}//address of items in n1://0xc20801e160//0xc20801e168//0xc20801e170fmt.Println("address of items in n2: ")for i := 0; i < len(n2); i++ {fmt.Printf("%p\n", &n2[i])}//address of items in n2://0xc20803a2d0//0xc20803a2d8//0xc20803a2e0//0xc20803a2e8引用“失效”
实现了删除slice最后一个item的函数12345func rmLast(a []int) {fmt.Printf("[rmlast] the address of a is %p", a)a = a[:len(a)-1]fmt.Printf("[rmlast] after remove, the address of a is %p", a)}调用此函数后,发现原来的slice并没有改变
1234567func main() {xyz := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}fmt.Printf("[main] the address of xyz is %p\n", xyz)rmLast(xyz)fmt.Printf("[main] after remove, the address of xyz is %p\n", xyz)fmt.Printf("%v", xyz) //[1 2 3 4 5 6 7 8 9]}打印出来的结果如下:
12345[main] the address of xyz is 0xc2080365f0[rmlast] the address of a is 0xc2080365f0[rmlast] after remove, the address of a is 0xc2080365f0[main] after remove, the address of xyz is 0xc2080365f0[1 2 3 4 5 6 7 8 9]这里直接打印了slice的指针值,因为slice是引用类型,所以指针值都是相同的,我们换成打印slice的地址看下
123456789101112func rmLast(a []int) {fmt.Printf("[rmlast] the address of a is %p", &a)a = a[:len(a)-1]fmt.Printf("[rmlast] after remove, the address of a is %p", &a)}func main() {xyz := []int{1, 2, 3, 4, 5, 6, 7, 8, 9}fmt.Printf("[main] the address of xyz is %p\n", &xyz)rmLast(xyz)fmt.Printf("[main] after remove, the address of xyz is %p\n", &xyz)fmt.Printf("%v", xyz) //[1 2 3 4 5 6 7 8 9]}结果:
12345[main] the address of xyz is 0xc20801e1e0[rmlast] the address of a is 0xc20801e200[rmlast] after remove, the address of a is 0xc20801e200[main] after remove, the address of xyz is 0xc20801e1e0[1 2 3 4 5 6 7 8 9]这次可以看到slice作为函数参数传入函数时,实际上也是拷贝了一份slice,因为slice本身是个指针,所以从现象来看,slice是引用类型